Possible results: 36
[tex]\begin{gathered} \lbrace(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3) \\ (3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6) \\ (6,1)(6,2)(6,3)(6,4)(6,5)(6,6)\rbrace \end{gathered}[/tex]Results that sum 2 or 5: 5
[tex]\lbrace(1,1)(1,4)(2,3)(3,2)(4,1)\rbrace[/tex]Then, the probability of winning on your next turn is:
[tex]\begin{gathered} p(2or5)=\frac{\#\text{results that sum 2 or 5}}{\#possibl\text{e results}} \\ \\ p(2or5)=\frac{5}{36}=0.13 \\ \\ \\ \end{gathered}[/tex]In percentage: 13%