Question

Divide (y with the exponent of 3-1) divided by (y+4)

Answer 1

Procedure

$\begin{gathered} \frac{y^3-1}{y+4} \\ \frac{y^3}{y+4}-\frac{1}{y+4} \end{gathered}$

y^3/(y+4) - 1/(y+4)

Alternate forms

$y^2-4y+16-\frac{65}{y+4}$