Given:
(-2, -2), (-1, 0), (0, 2). As it is a linear relation we can represent it in the form y = mx + b; where m is the slope (rate of change) and b the y - intercept.
To find the slope:
[tex]m\text{ = }\frac{y_2-y_2}{x_2-x_1}=\frac{0+2}{-1+2}=2[/tex]
The rate of change is 2.
Taking one point and replacing it in the formula (y = mx + b):
2 = 2(0) + b
2 = b
Then, the formula is y = 2x + 2; graphing it:
when x = 1;
y = 2(1) + 2
y = 4
(1, 4)
when x = 2
y = 2(2) + 2
y = 6
(2, 6)
