Question

A circuit with a 25 V battery a 7 Ω resistor and 5 Ω resistor in series. What is the current throughout the circuit?

Answer 1

First, let's calculate the total resistance in the circuit.

Since the two resistors are in series, the total resistance is the sum of each resistance:

$R=7+5=12$

Now, to calculate the current, we can divide the voltage by the total resistance:

$\begin{gathered} I=\frac{V}{R} \\ I=\frac{25}{12} \\ I=2.083\text{ A} \end{gathered}$

Therefore the current is 2.083 A.