Compound Interest
The final value of an investment P deposited at an interest rate r for t years is:
[tex]FV=P\cdot(1+\frac{r}{m})^{t\cdot m}[/tex]Where m is the number of times the investment earns interest in a year (compounding times per year).
In the problem, P = $16,000, r = 10% = 0.1, t = 8, and m = 4 (there are 4 quarters in a year).
Applying the formula:
[tex]\begin{gathered} FV=\$16,000\cdot(1+\frac{0.1}{4})^{4\cdot8} \\ \text{Operating:} \\ FV=\$16,000\cdot(1.025)^{32} \\ FV=\$16,000\cdot2.20376 \\ FV=\$35,260.11 \end{gathered}[/tex]Now we can calculate the amount of interest earned by subtracting:
I = FV - P
I = $35,260.11 - $16,000
I = $19,260.11