Answer:
3y-4= 17
Explanation:
First, we have to find the value of y from 2y - 6 = 8.
Adding 6 to both sides gives
[tex]2y=8+6[/tex][tex]\Rightarrow2y=14[/tex]dividing both sides by 2 gives
[tex]\frac{2y}{2}=\frac{14}{2}[/tex][tex]\Rightarrow\boxed{y=7.}[/tex]With the value of y in hand, we can now evaluate 3y - 4.
Putting in y = 7 into 3y - 4 gives
[tex]3(7)-4=17[/tex]Hence,
[tex]\boxed{3y-4=17.}[/tex]