Respuesta :
We need to solve the next system of equations:
[tex]\begin{gathered} 5x+6y+3z=-1 \\ 3x+5y+4z=-5 \\ -x-2y-2z=5 \end{gathered}[/tex]Lets pair equations to eliminate one variable:
[tex]\begin{gathered} 5x+6y+3z=-1 \\ 3x+5y+4z=-5 \end{gathered}[/tex]Multiply the first equation by -3 and the second equation by 5:
[tex]\begin{gathered} -3(5x+6y+3z=-1) \\ 5(3x+5y+4z=-5) \end{gathered}[/tex]Then, add equations:
[tex]\begin{gathered} -15x-18y-9z=3 \\ 15x+25y+20z=-25 \\ ------------ \\ 0+(-18y+25y)+(-9z+20z)=(3-25) \\ ----------------------- \\ 7y+11z=22 \end{gathered}[/tex]The second pair :
[tex]\begin{gathered} 3x+5y+4z=-5 \\ -x-2y-2z=5 \end{gathered}[/tex]Multiply the first equation by 1 and the second equation by 3:
[tex]\begin{gathered} 1(3x+5y+4z=-5) \\ 3(-x-2y-2z=5) \\ \\ \end{gathered}[/tex]Add both equations:
[tex]\begin{gathered} 3x+5y+4z=-5 \\ -3x-6y-6z=15 \\ ------------- \\ 0+(5y-6y)+(4z-6z)=-5+15 \\ ------------------------ \\ -y-2z=10 \end{gathered}[/tex]Solve the new system:
[tex]\begin{gathered} 7y+11z=22 \\ -y-2z=10 \end{gathered}[/tex]Multiply the first equation by 1 and the second equation by 7:
[tex]\begin{gathered} 1(7y+11z=22) \\ 7(-y-2z=10) \\ \\ \end{gathered}[/tex]Add both equations:
[tex]\begin{gathered} 7y+11z=22 \\ -7y-14z=70 \\ ------------- \\ 0+(11z-14z)=-22+70 \\ ---------------- \\ -3z=48 \\ z=-16 \end{gathered}[/tex]Replace the z value on one equation:
[tex]-y-2(-16)=10[/tex]Solve for y:
[tex]\begin{gathered} -y+32=10 \\ \\ -y=10-33 \\ y=22 \end{gathered}[/tex]Finally, replace the y value and the z value:
[tex]\begin{gathered} -x-2y-2z=5 \\ -x-2(22)-2(-16)=5 \\ -x-44+32=5 \\ -x-12=5 \\ -x=5+12 \\ x=-17 \end{gathered}[/tex]Hence, the result for the variables are:
x=-17
y=22
z=-16