The slope-intercept form is given by
[tex]y=mx+b_{}[/tex]Where m is the slope, b is the y-intercept.
Let us convert the given equations into the slope-intercept form.
[tex]y-6=-2\mleft(x+2\mright)[/tex]Expand the parenthesis on the right and then separate the y variable on the left side.
[tex]\begin{gathered} y-6=-2x-4 \\ y=-2x-4+6 \\ y=-2x+2 \end{gathered}[/tex]Similarly, repeat the above process for the 2nd equation
[tex]\begin{gathered} y-8=3\mleft(x+5\mright) \\ y-8=3x+15_{} \\ y=3x+15+8_{} \\ y=3x+23 \end{gathered}[/tex]Finally, the 3rd equation
[tex]\begin{gathered} y-\frac{1}{2}=x+\frac{1}{2} \\ y=x+\frac{1}{2}+\frac{1}{2} \\ y=x+1 \end{gathered}[/tex]Therefore, the equations in the slope-intercept form are
[tex]\begin{gathered} 21.\: \: y=-2x+2 \\ 24.\: \: y=3x+23 \\ 27.\: \: y=x+1 \end{gathered}[/tex]