From the information provided, we have a total of 103 coins. We do not know the number of dimes and quarters but its all a total of $15.25. This can be rewritten as 1525 cents.
Note also that;
[tex]\begin{gathered} 10\text{dimes}=\text{ \$1}=100\text{cents} \\ 4\text{quarters}=\text{ \$1}=100cents \end{gathered}[/tex]For the total number of coins, we would have;
[tex]\begin{gathered} d+q=103---(1) \\ \end{gathered}[/tex]For the total amount of money available, we would have;
[tex]10d+25q=1525---(2)[/tex]We would now take equation (1). Make d the subject of the equation and we'll have;
[tex]d=103-q[/tex]Substitute for d into equation (2);
[tex]\begin{gathered} 10d+25q=1525 \\ 10(103-q)+25q=1525 \\ 1030-10q+25q=1525 \end{gathered}[/tex]We can now collect like terms, and we'll have;
[tex]\begin{gathered} 25q-10q=1525-1030 \\ 15q=495 \\ \end{gathered}[/tex]We next divide both sides by 15;
[tex]\begin{gathered} \frac{15q}{15}=\frac{495}{15} \\ q=33 \end{gathered}[/tex]This means we have 33 quarters. We can now substitute for the value of q into equation (1);
[tex]\begin{gathered} d+q=103 \\ d+33=103 \\ d=103-33 \\ d=70 \end{gathered}[/tex]ANSWER:
We now have,
70 dimes and 33 quarters