Given
The mean and standard deviation of the given distribution is,
[tex]\begin{gathered} \mu=100 \\ \sigma=20 \end{gathered}[/tex]To find the probability that a randomly selected adult has an IQ less than 124.
Explanation:
It is given that,
The mean and standard deviation of the given distribution is,
[tex]\begin{gathered} \mu=100 \\ \sigma=20 \end{gathered}[/tex]Then, for x=124,
[tex]\begin{gathered} z=\frac{x-\mu}{\sigma} \\ =\frac{124-100}{20} \\ =\frac{24}{20} \\ =\frac{6}{5} \\ =1.2 \end{gathered}[/tex]Then,
[tex]\begin{gathered} P(x<124)=P(z<1.2) \\ =0.3849 \end{gathered}[/tex]Hence, the answer is 0.3849.