Question

Factor each trinomial if the trinomial cannot be factored, write prime. show work1.) x^2-11x+302.) x^2+10x+9

Answer 1

1) the initial expression is:

$x^2-11x+30$

So we have to find two numbers that added is equal to -11 and multiply equal to 30 so the expression can be writen as:

$(x-6)(x-5)$

because

$\begin{gathered} -6-5=-11 \\ -6\cdot-5=30 \end{gathered}$

2) the initial expression is:

$x^2+10x+9$

so we need two numbers that added are equal to 10 and multiply equal to 9 so:

$(x+9)(x+1)$

because:

$\begin{gathered} 9+1=10 \\ 9\cdot1=9 \end{gathered}$