Question

If c and d are constants, what is the slope of a line that is perpendicular to the line cx + dy - b = 3?

Answer 1

Let's remember the slope-intercept form of a line:

$y=mx+b$

in which m is the slope and b is the point at which it intercepts the y-axis.

Now, let's make it so the equation we were given is in this form:

$c\cdot x+d\cdot y-b=3$$d\cdot y=3+b-c\cdot x$$y=-\frac{c}{d}\cdot x+\frac{3+b}{d}$

With this we can see that the slope of the given line is -c/d.