we have
2x^2-5x+2=0
using the formula to solve quadratic equations
we have
a=2
b=-5
c=2
substitute in the formula
[tex]\begin{gathered} x=\frac{5\pm\sqrt[\square]{-5^2-4(2)(2)}}{2(2)} \\ \\ x=\frac{5\pm\sqrt[\square]{9}}{4} \\ \\ x=\frac{5\pm3}{4} \end{gathered}[/tex]
therefore
the solutions are
x=2
x=1/2
