the coordinate of B is (4,0)
and D is (8, 10)
the coordinate of C is (4,5) and D is (8, 10)
so the equation of the line passing through two-point is given as follows,
[tex]\begin{gathered} y-4=\frac{10-5}{8-4}(x-5) \\ y-4=\frac{5}{4}(x-5) \\ \end{gathered}[/tex]
for point (16, 20)
substitute the value of x and y in the above expression
[tex]\begin{gathered} 20-4=\frac{5}{4}(16-5) \\ 16\ne\frac{55}{4} \end{gathered}[/tex]
so it is not satisfying the equation of the line that means the point does not lie on this line