Question

Use the laws of exponents to simplify expressions with rational exponents Number 573

Answer 1

SOLUTION

$(h^6)^{\frac{4}{3}},(k^{12})^{\frac{3}{4}},(j^{10})^{\frac{7}{10}}$

This expressions are simplified as

$\begin{gathered} h^{6\times\frac{4}{3}}=h^8 \\ k^{12\times\frac{3}{4}}=k^9 \end{gathered}$

The last solution is:

$(j^{10})^{\frac{7}{5}}=j^{14}$