A wrench with a 20 cm handle has a force 80 N applied to the end, perpendicular to the direction of the handle. What torque does this produce on the wrench?

Given data
*The given distance is l = 20 cm = 0.2 m
*The given force applied to the end is F = 80 N
The formula for the torque is given as
[tex]\tau=F\times l[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \tau=(80)\times(0.2) \\ =16\text{ N.m} \end{gathered}[/tex]