We will solve as follows:
The shape is a rectangle triangle with a side of 30 and other side of 12. We calculate the hypotenuse:
[tex]h=\sqrt[]{12^2+30^2}\Rightarrow h=6\sqrt[]{29}[/tex]Now, using the law of sines, we solve:
[tex]\frac{6\sqrt[]{29}}{\sin(90)}=\frac{30}{\sin (\alpha)}[/tex]Now we solve for alpha:
[tex]\Rightarrow\sin (\alpha)=\frac{30\sin(90)}{6\sqrt[]{29}}\Rightarrow\alpha=\sin ^{-1}(\frac{30\sin(90)}{6\sqrt[]{29}})[/tex]From this we will have that the angle of elevation when she looks is of aproximately 68.2°.