Respuesta :
Step 1
Write the system of equations required to solve the problem
[tex]\begin{gathered} 0.4x+0.25y=0.3(5.25)----(1) \\ x+y=5.25_{}---(2) \\ \text{where ;} \\ x\text{ represents the 40}\%\text{ gloss gallon} \\ y\text{ represents the 25}\%\text{ gloss gallon} \end{gathered}[/tex]Step 2
Find the value of x using the substitution method
Find the value of y from equation 2
[tex]\begin{gathered} x+y=5.25 \\ y=5.25-x \end{gathered}[/tex]Substitute for y as seen above in equation 1
[tex]\begin{gathered} 0.4x+0.25y=0.3(5.25) \\ 0.4x+0.25(5.25-x)=1.575_{} \\ 0.4x+1.3125-0.25x=1.575 \\ 0.4x-0.25x=1.575-1.3125 \\ 0.15x=0.2625 \\ \frac{0.15x}{0.15}=\frac{0.2625}{0.15} \\ x=1.75\text{ or }\frac{7}{4}\text{ or 1}\frac{3}{4} \end{gathered}[/tex]Step 3
Find the value of y by substituting for x in equation 2
[tex]\begin{gathered} x+y=5.25_{} \\ 1.75+y=5.25 \\ y=5.25-1.75 \\ y=\frac{7}{2}or\text{ 3.5 or 3}\frac{1}{2} \end{gathered}[/tex]Therefore,
[tex]\text{There are 1}\frac{3}{4\text{ }}\text{ gallons of 40\% gloss and 3}\frac{1}{2}\text{ gallons of 25\% gloss}[/tex]The answer is, therefore, option C