Find the vertical asymptote of the graph of the function.f(x)= 1 —————- (x-2)^2 The equation of the vertical asymptote isX=

Answer:
The eqaution is given below as
[tex]f(x)=\frac{1}{(x-2)^2}[/tex]Concept:
A vertical asymptote is a vertical line that guides the graph of the function but is not part of it. It can never be crossed by the graph because it occurs at the x-value that is not in the domain of the function.
To do this, we will have to look for the value of x that makes the equation undefined.
That is, we will susbtitute the denominator=0
By applying the concept,we will have
[tex]\begin{gathered} (x-2)^2=0 \\ sqare\text{ root both sides, we will have} \\ x-2=0 \\ add\text{ 2 to both sides,we will have} \\ x-2+2=0+2 \\ x=2 \end{gathered}[/tex]Representing graphically, we will have the vertical symptotes to be
Hence,
The equation of the vertical asymptote is
[tex]x=2[/tex]