Question

A man is dieting for three weeks. if a man loses 5 5/6 pounds the first week, 5 4/5 pounds the second week, and 3 2/3 pounds the third week, what is the average weekly weight loss? write the solution as a mixed number or a fraction in lowest terms.

Answer 1

Given:

A man is dieting for three weeks

The man loses 5 5/6 pounds the first week, 5 4/5 pounds the second week, and 3 2/3 pounds the third week

So, the sum of the pounds =

$5\frac{5}{6}+5\frac{4}{5}+3\frac{2}{3}=\frac{153}{10}$

So, the average weekly weight loss =

$\frac{153}{10}\div3=\frac{153}{10}\times\frac{1}{3}=\frac{153}{30}=\frac{51}{10}=5\frac{1}{10}$

So, the answer will be:

the average weekly weight loss 5 1/10 pounds