The side length of the Rhombus is 13 cm
Here, we want to get the measure of the side length of the Rhombus
We start with a diagrammatic representation of the given information as follows;
Where AC and BD represents the diagonal lengths
Let AC = 10 cm and BD equals 24 cm
Mathematically, the diagonals bisect each other at right angles
Thus, we have it that;
[tex]\begin{gathered} AO\text{ = }\frac{1}{2}\times AC\text{ = }\frac{1}{2}\times\text{ 10 cm = 5 cm} \\ \\ BO\text{ = }\frac{1}{2}\times\text{ BD = }\frac{1}{2}\times\text{ 24 cm = 12 cm} \end{gathered}[/tex]Since we have a right angle, it follows that AOB is a right triangle with the side length of the rhombus being the hypitenuse as it is the side that faces the right triangle
From Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Thus, we have it that;
[tex]\begin{gathered} AB^2=5^2+12^2 \\ AB^2\text{ = 169} \\ AB\text{ = }\sqrt[]{169} \\ AB\text{ = 13} \end{gathered}[/tex]