Given:
The number of turns in the coil is N = 120 turns
The emf induced in the coil is
[tex]\epsilon\text{ = 1.2 V}[/tex]The change in the magnetic field is
[tex]\begin{gathered} \Delta B=\text{ 1.5-0.1} \\ =1.4\text{ T} \end{gathered}[/tex]The area of the coil is
[tex]\begin{gathered} A\text{ = 0.15}\times0.3 \\ =0.045\text{ m}^2 \end{gathered}[/tex]To find the time interval.
Explanation:
The time interval can be calculated by the formula
[tex]\Delta t=\frac{NA\Delta B}{\epsilon}[/tex]On substituting the values, the time interval will be
[tex]\begin{gathered} \Delta t\text{ = }\frac{120\times0.045\times1.4}{1.2} \\ =6.3\text{ s} \end{gathered}[/tex]Final Answer: The time interval is 6.3 s