Question

How much work is required to lift a 2.87 kg object from the bottom of a well 10.7 m deep? answer in:___J

Answer 1

We will determine the work as follows:

First, we recall that:

$W=Fs$

Then:

$W=(2.87kg\ast9.8m/s^2)(10.7m)\Rightarrow W=300.9482J$

So, the work will be 300.9482 Joules.