Question

Determine the range of the function f(x)=3/2 (x+2) when the domain is {-4,-2,2?

Answer 1

$f(x)=\frac{3}{2}(x+2)$

Let's evaluate the function for the interval:

[-4,-2.2]

$\begin{gathered} f(-4)=\frac{3}{2}(-4+2) \\ f(-4)=\frac{3}{2}(-2) \\ f(-4)=-3 \end{gathered}$$\begin{gathered} f(-2.2)=\frac{3}{2}(-2.2+2) \\ f(-2.2)=-0.3 \end{gathered}$

Therefore, the range is:

$R\colon\lbrack-3,-0.3\rbrack$