The given problem states you have a triangle that can be divides into 2 smaller right triangles that can be used to solve the missing sides x and y.
Starting from the left triangle to the left we can use the pythagorean to solve for x
The missing side of the triangle is the hypotenuse and using the pythagorean we obtain:
[tex]\begin{gathered} a^2+b^2=c^2 \\ 9^2+5^2=x^2 \\ 81+25=x^2 \\ 106=x^2 \\ x=\sqrt[]{106} \\ \end{gathered}[/tex]
Applying the same concept, solve side y using the pythagorean on the triangle to the right
In this triangle the missing side is also the hypotenuse, applying the pythagorean we obtain:
[tex]\begin{gathered} a^2+b^2=c^2 \\ 3^2+5^2=y^2 \\ 9+25=y^2 \\ 34=y^2 \\ y=\sqrt[]{34} \end{gathered}[/tex]
simplify the radicals by decomposing the numbers inside the roots into primes.
none of the radicals can be simplified.
ANSWER:
[tex]x=\sqrt[]{106};y=\sqrt[]{34}[/tex]
