Question

what is the volume of the cone with a diameter of 2.8in and an aproximate height of 3in?

Answer 1

The volume of a cone is:

$V=\frac{1}{3}\times h\times\pi\times r^2$

Then, We have:

$V=\frac{1}{3}\times\pi\times3in\times(\frac{2.8}{2}in)^2$

The volume of the cone is:

$V\approx6.1575\text{ }in^3\approx6in^3$