Question

At what temperature in Kelvin will 50.01 moles of neon at a pressure of 1.01 atm occupy a volume of 237L?

Answer 1

ANSWER

The temperature of neon gas is 58.31K

EXPLANATIONS

Given that;

The pressure of neon gas is 1.01 atm

The volume of the gas is 237L

The number of moles of the gas is 50.01 moles

Follow the steps below to find the temperature of the gas

Step 1; Apply the ideal gas equation

$\text{ PV = nRT}$$\text{ Where R is 0.0821 L.atm. mol}^{-1}.\text{ K}^{-1}$

Substitute the given data into the above formula

$\begin{gathered} \text{ 1.01 }\times\text{ 237 = }\times50.01\times\text{ 0.0821 }\times\text{ T} \\ 239.37\text{ = 4.105T} \\ \text{ Divide both sides by 4.105} \\ \text{ T = }\frac{\text{ 239.37}}{\text{ 4.105}} \\ \\ \text{ T = 58.311 K} \end{gathered}$

Therefore, the temperature of neon gas is 58.31K