Respuesta :

we have the expression

[tex]\sqrt[]{\frac{128x^5y^6}{2x^7y^5}}[/tex]

simplify

we have that

128/2=64=2^6

(x^5y^6)/(x^7y^5)=y/x^2

substitute in the original expression

[tex]\sqrt[]{\frac{2^6y}{x^2^{}}}=\frac{2^3}{x}\sqrt[]{y}=\frac{8}{x}\sqrt[]{y}[/tex]

ACCESS MORE
EDU ACCESS