Let's assume it is a linear function of the form:
[tex]f(x)=mx+b[/tex]Let:
[tex]\begin{gathered} x=2,f(x)=-8 \\ x=5,f(x)=-20 \\ ----- \\ so\colon \\ -8=2m+b_{\text{ }}(1) \\ -20=5m+b_{\text{ }}(2) \end{gathered}[/tex]Using elimination method:
[tex]\begin{gathered} (1)-(2) \\ -8-(-20)=2m-5m+b-b \\ 12=-3m \\ m=\frac{12}{-3} \\ m=-4 \end{gathered}[/tex]so, replacing the value of m into (1):
[tex]\begin{gathered} -8=2(-4)+b \\ -8=-8+b \\ b=8-8 \\ b=0 \end{gathered}[/tex]Therefore, the function is given by:
[tex]f(x)=-4x[/tex]