Question

the following table presents the probability distribution of the number of vacations X taken last year for a randomly chosen family. compute the mean X. 0. 1. 2. 3. 4p(x) 0.13. 0.61. 0.15. 0.07. 0.04

Answer 1

SOLUTION

The table for the x and P(x) can be shown below

From the table above, mean for the data is calculated as

$\begin{gathered} \bar{x}=\sum_^x.p(x) \\ \sum_^x.p(x)=1.28 \end{gathered}$

Hence the answer is 1.28