1.
(b)
The slope-intercept form of a line is given by:
[tex]\begin{gathered} y=mx+b \\ where\colon \\ m=slope \\ b=y-intercept_{}_{} \end{gathered}[/tex]So:
[tex]\begin{gathered} 6x+10y=8 \\ solve_{\text{ }}for_{\text{ }}y\colon \\ 10y=8-6x \\ y=\frac{8-6x}{10} \\ y=\frac{8}{10}-\frac{6x}{10} \\ y=\frac{4}{5}-\frac{3}{5}x \end{gathered}[/tex]From the equation, we can conclude:
[tex]\begin{gathered} b=\frac{4}{5} \\ m=slope=-\frac{3}{5} \end{gathered}[/tex]