Respuesta :

[tex]\begin{gathered} SR=\sqrt[]{QR^2+SQ^2} \\ SR=\sqrt[]{24^2+7^2} \\ SR=\sqrt[]{625} \\ SR=25 \end{gathered}[/tex]

Therefore:

[tex]\frac{OP}{SQ}=\frac{OR}{SR}[/tex][tex]\begin{gathered} \frac{14}{7}=\frac{OR}{25} \\ so\colon \\ OR=25\cdot2 \\ OR=50 \end{gathered}[/tex]

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