[tex]\begin{gathered} 4x-3y=13 \\ x=\frac{13+3y}{4} \\ 17\cdot\frac{13+3y}{4}-y=-7 \\ \frac{221+47y}{4}=-7 \\ y=-\frac{249}{47} \\ then\text{ y in x } \\ x=\frac{13+3\left(-\frac{249}{47}\right)}{4}=-\frac{34}{47} \\ \text{the point are (}-\frac{34}{47},-\frac{249}{47}) \end{gathered}[/tex]
therefore is false
