(2x+y)(y+3) drawn as a rectangle
Length= (2x+y)
width= (y+3)
where a is a value that depends on x and y
Solution)
Apply FOIL method
[tex]\mleft(a+b\mright)\mleft(c+d\mright)=ac+ad+bc+bd[/tex][tex]\mleft(2x+y\mright)\mleft(y+3\mright)=2xy+2x\cdot\: 3+yy+y\cdot\: 3[/tex]
then, the area is
[tex]=2xy+6x+y^2+3y[/tex]
we can draw this the following way
