By Compound Angles Theorem,
[tex]\begin{gathered} \sin (\frac{4\pi}{3})=\sin (\frac{2\pi}{3}+\frac{2\pi}{3})=2\sin (\frac{2\pi}{3})\cos (\frac{2\pi}{3})=2(\frac{\sqrt[]{3}}{2})(-\frac{1}{2})=-\frac{\sqrt[]{3}}{2} \\ \end{gathered}[/tex]Recall:
[tex]\begin{gathered} \sin (\frac{2\pi}{3})=\frac{\sqrt[]{3}}{2} \\ \\ \cos (\frac{2\pi}{3})=-\frac{1}{2} \end{gathered}[/tex]Hence, the correct answer is
[tex]-\frac{\sqrt[]{3}}{2}[/tex]