Question

find 2 integers between which each radical belongs $\sqrt{91}$

Answer 1

Answer:

9 and 10

Explanation:

First, determine two perfect squares: One less than and one greater than 91.

$81<91<100$

Take the square roots:

$\begin{gathered} \sqrt[]{81}<\sqrt[]{91}<\sqrt[]{100} \\ =9<\sqrt[]{91}<10 \end{gathered}$

Thus, radical √91 is between integers 9 and 10.