Question

if the area of a rectangular room is 3x² + 8x + 4q1. find the dimensions of the roomq2. if x=2 feet, what is the area of the roomq3. if you selected for the room cost 4.49 a square foot, how much would it cost to tile the whole room

Answer 1

To find the dimensions of the room we have to factor the expression:

$3x^2+8x+4$

To do this we need to find to factor for 3 and 4. For three we have the options 3 and 1, for 4 we have the options 2 by 2. Then we cross multiply this factors, in this case we get 2*2=6 and 2*1=2. Since the sum is 8 that means that:

$3x^2+8x+4=(3x+2)(x+2)$

Therefore the dimensions of the rectangle are (3x+2) and (x+2).

Now, if x=2 then the area of the room is:

$3(2)^2+8(2)+4=32$

Therefore the area is 32 squared feet.

If each square feet cost $4.49 to tile then the total cost will be:

$32\cdot4.49=143.68$

Therefore it will cost $143.68 to tile the floor.