Answer:
2⅓ feet per second.
Explanation:
10 seconds after he entered the water, the depth of the diver = 30 feet
40 seconds after he entered the water, the depth of the diver = 100 feet
The scuba diver's average rate of change
[tex]\begin{gathered} =\frac{\text{Change in Depth}}{\text{Change in time}} \\ =\frac{100-30}{40-10} \\ =\frac{70}{30} \\ =2\frac{1}{3}\text{ feet per second} \end{gathered}[/tex]The scuba diver's average rate of change is 2⅓ feet per second.
In the context of this scenario, it means the scuba diver descends a depth of 2⅓ feet every second.