Question

Divide polynomial by monomial (8x^3 + 6x^2) / 2x

Answer 1

$\begin{gathered} \frac{8x^3+6x^2}{2x}=\frac{8x^3}{2x}+\frac{6x^2}{2x} \\ \frac{8x^3}{2x}+\frac{6x^2}{2x}=\frac{8}{2}x^{3-1}+\frac{6}{2}x^{2-1}^{} \\ \frac{8}{2}x^{3-1}+\frac{6}{2}x^{2-1}=4x^2+3x \end{gathered}$