The conveyor belt is approximately 70.7 feet long and rises from the ground at 45 degrees. What is
the height of the silo?
Step 1
here we have a right triangle, we can use sine function
[tex]\begin{gathered} \text{for a rigth triangle} \\ \sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{isolate opposite side} \\ \text{opposite side=hypotenuse }\cdot\sin \theta \end{gathered}[/tex]then,
Let
conveyor belt = hypotenuse=70.7 ft
hypotenuse=70.7
the height of the silo=oppsite side=leg2=opposite side
angle= 45 degrees
Step 2
Replace
[tex]\begin{gathered} \text{opposite side=hypotenuse}\cdot\sin \theta \\ \text{opposite side=}70.7\text{ ft }\cdot\sin \text{ 45} \\ \text{opposite side=49.99 ft} \end{gathered}[/tex]Round to the nearest foot,
[tex]49.99\cong50[/tex]so, the height of the silo is 50 ft