Question

Find C on line segment AB that is 2/5 the distance from A(0, 0) to B(10,20).

Answer 1

In order to find the point C, which is located at 2/5 of the distance, we can calculate separately the x and y coordinates.

For the x-coordinate, the horizontal distance is the x-coordinate of the second point minus the x-coordinate of the first point:

$10-0=10$

Now we just need to find 2/5 of this distance:

$\frac{2}{5}\cdot10=\frac{20}{5}=4$

So the x-coordinate of the point C is 4.

Now, calculating the y-coordinate, the vertical distance is the y-coordinate of the second point minus the y-coordinate of the first point:

$20-0=20$

Now, calculating 2/5 of this distance, we have:

$\frac{2}{5}\cdot20=\frac{40}{5}=8$

So the y-coordinate of point C is 8.

Therefore the coordinates of point C are (4, 8)