The payout annuity formula is the following:
[tex]P_0=\frac{d(1-(1+\frac{r}{k})^{-N\cdot k}}{(\frac{r}{k})}[/tex]Where:
Po is starting amount in the account
d is the regular withdrawal
r is the annual interest rate (in decimal form)
k is the number of compounding periods in one year
N is the number of years we plan to take withdrawals.
The given information is:
Po=$567,625
r=4.8%/100%=0.048
k=12 since we are withdrawing monthly
N=19 years.
By replacing this information in the formula, we can solve for d as follows:
[tex]\begin{gathered} 567,625=\frac{d(1-(1+\frac{0.048}{12})^{-19\cdot12})}{(\frac{0.048}{12})} \\ 567,625=\frac{d(1-(1+0.004)^{-228})}{(0.004)} \\ 567,625=\frac{d(1-(1.004)^{-228})}{(0.004)} \\ 567,625=\frac{d(1-0.4025)}{(0.004)} \\ 567,625=\frac{d(0.5975)}{(0.004)} \\ 567,625\cdot(0.004)=d(0.5975) \\ 2270.5=d(0.5975) \\ d=\frac{2270.5}{0.5975} \\ d=3799.69 \end{gathered}[/tex]Answer: you will be able to pull out each month $3799.69 for 19 years