We have to solve the expression:
[tex]\begin{gathered} \frac{9}{2}-(3+\frac{1}{3}) \\ \frac{9}{2}-3-\frac{1}{3} \\ -3+\frac{9}{2}-\frac{1}{3} \\ -3+\frac{9\cdot3-1\cdot2}{2\cdot3} \\ -3+\frac{27-2}{6} \\ -3+\frac{25}{6} \\ -3+\frac{24+1}{6} \\ -3+\frac{24}{6}+\frac{1}{6} \\ -3+4+\frac{1}{6} \\ 1+\frac{1}{6} \end{gathered}[/tex]Answer: the expression is equal to 1 1/6.
