Answer:
There is no real solution
The solutions are imaginary, and they are:
[tex]r=\sqrt[]{-10}[/tex]and
[tex]r=-\sqrt[]{-10}[/tex]Explanation:
Given the equation:
[tex]\frac{1}{2}r^2-10=\frac{3}{2}r^2[/tex]To solve this, first subtract
[tex]\frac{1}{2}r^2[/tex]from both sides of the equation
[tex]\begin{gathered} \frac{1}{2}r^2-10-\frac{1}{2}r^2=\frac{3}{2}r^2-\frac{1}{2}r^2 \\ \\ -10=r^2 \end{gathered}[/tex]Next, take square root of both sides
[tex]r=\pm\sqrt[]{-10}[/tex]The solutions are:
[tex]\begin{gathered} r=\sqrt[]{-10} \\ \\ \text{and} \\ \\ r=-\sqrt[]{-10} \end{gathered}[/tex]There is no real solution, only imaginary.