Solve 1/2r^2-10= 3/2r2 using square roots. Select the solution(s).POSSIBLE SOLUTIONSA) r=(radical symbol here) -10B) r= -(radical symbol here) -10C) r= -(radical symbol here) 5D) r= (radical symbol here) 5E) no real solution

Respuesta :

Answer:

There is no real solution

The solutions are imaginary, and they are:

[tex]r=\sqrt[]{-10}[/tex]

and

[tex]r=-\sqrt[]{-10}[/tex]

Explanation:

Given the equation:

[tex]\frac{1}{2}r^2-10=\frac{3}{2}r^2[/tex]

To solve this, first subtract

[tex]\frac{1}{2}r^2[/tex]

from both sides of the equation

[tex]\begin{gathered} \frac{1}{2}r^2-10-\frac{1}{2}r^2=\frac{3}{2}r^2-\frac{1}{2}r^2 \\ \\ -10=r^2 \end{gathered}[/tex]

Next, take square root of both sides

[tex]r=\pm\sqrt[]{-10}[/tex]

The solutions are:

[tex]\begin{gathered} r=\sqrt[]{-10} \\ \\ \text{and} \\ \\ r=-\sqrt[]{-10} \end{gathered}[/tex]

There is no real solution, only imaginary.

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