Question

g(x) = sqr root of x+3What is the domain of g(x)

Answer 1

Answer:

$\lbrack-3,\infty)$

Given:

$g(x)=\sqrt[]{x+3}$

We need to find the values of x in which the value inside the radical should not be negative:

$\begin{gathered} x+3\ge0 \\ x\ge-3 \end{gathered}$

This will now give us a domain of:

$\lbrack-3,\infty)$