The picture represents 10 gumballs, and 5 chocolate chewy.
Consider that the probability of an event is given by,
[tex]\text{Probability}=\frac{\text{ No. of favorable outcomes}}{\text{Total no. of outcomes}}[/tex]
The probability of choosing a chocolate chewy and then a gumball withou replacement, is calculated as,
[tex]\begin{gathered} P(\text{ chocolate chewy then gumball)}=\frac{\text{ No. of chocolate chewy}}{\text{Total number of items}}\times\frac{\text{ No. of gumballs}}{\text{Total no. of items left}} \\ P(\text{chocolate chewy then gumball)}=\frac{5}{15}\times\frac{10}{14} \\ P(\text{chocolate chewy then gumball)}=\frac{5}{21} \end{gathered}[/tex]
Thus, the required probability is 5/21 .
