Question

Between points A and B, the cyclist increases his speed from 2m/s to 5 m/s in a time of 2 seconds. What is the magnitude of his acceleration?

Answer 1

Answer:

1.5 m/s²

Explanation:

The acceleration can be calculated as the change in velocity over time. So, the magnitude of his acceleration is equal to

$\begin{gathered} a=\frac{v_B-v_A}{t} \\ \\ a=\frac{5\text{ m/s - 2 m/s}}{2\text{ s}} \\ \\ a=\frac{3\text{ m/s}}{2\text{ s}} \\ \\ a=1.5\text{ m/s}^2 \end{gathered}$

Therefore, the acceleration is 1.5 m/s²