Solution
Given the expression below
[tex]\frac{1}{3}(6x+12-3)[/tex]To find the equivalence of the given expression, we simplify the expression
[tex]\begin{gathered} \frac{1}{3}(6x+12-3) \\ =\frac{1}{3}(6x+9) \\ =\frac{6x}{3}+\frac{9}{3} \\ =2x+3 \end{gathered}[/tex]Hence, the equivalence of the given expression is 2x + 3
