Question

v=6 when t=8,find if v varies t² and v in terms of t

Answer 1

If v varies with t², then equation is,

$\begin{gathered} v\propto t^2 \\ v=kt^2 \end{gathered}$

Here, k is constant.

Substitute 6 for v and 8 for t in the equation to determine the value of constant k.

$\begin{gathered} 6=k(8)^2 \\ 6=64k \\ k=\frac{6}{64} \end{gathered}$

The value of constant k is 6/64. So equation for v is,

$v=\frac{6}{64}t^2$