We have an expression and we have to fill the blank.
We will call this value C in order to solve the expression:
[tex]\begin{gathered} -7\left(6-4x\right)-2\left(Cx+8\right)=18x-58 \\ -42+28x-2Cx-16=18x-58 \\ (28-2C)x-58=18x-58 \end{gathered}[/tex]Now, we know that the expression (28-2C) has to be equal to 18, so we have:
[tex]\begin{gathered} 28-2C=18 \\ 28-18=2C \\ 10=2C \\ C=\frac{10}{2} \\ C=5 \end{gathered}[/tex]Then, the final expression has to be:
-7*(6-4x) - 2*(5x + 8) = 18x-58
[tex]-7\left(6-4x\right)-2\left(5x+8\right)=18x-58[/tex]